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Ex , 9 Differentiate functions in, 𝑥^sin𝑥 + 〖 (sin𝑥)〗^cos𝑥 Let y = 𝑥^sin𝑥 + 〖 (sin𝑥)〗^cos〖𝑥 〗 Let 𝑢 =𝑥^sin𝑥 & 𝑣 =〖 (sin𝑥)〗^cos𝑥 ∴ 𝑦 = 𝑢 + 𝑣 Differentiating sides 𝑤.𝑟.𝑡.𝑥. 𝑑𝑦/𝑑𝑥 = (𝑑 (𝑢 + 𝑣.
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Rapidez de Para calcular qué tan rápido crece (i.e., la tasa de) entre Δx: Δy Δx = f (x + Δx) − f (x) Δx. 4. Δx 0
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Question 12 if 𝑒^𝑥+ 𝑒^𝑦=𝑒^ (𝑥+𝑦), 𝑡ℎ𝑒𝑛 𝑑𝑦/𝑑𝑥 is: (a) 𝑒^ (𝑦−𝑥) (b) 𝑒^ (𝑥+𝑦) (c) 〖−𝑒〗^ (𝑦−𝑥) (d) 2 𝑒^ (𝑥−𝑦) Given 𝑒^𝑥+𝑒^𝑦=𝑒^ (𝑥 + 𝑦) 𝑒^𝑥+𝑒^𝑦=𝑒^𝑥.𝑒^𝑦 Dividing by 𝒆^𝒙.𝒆^𝒚 sides 𝒆.
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f ′ (x) = d f d x. or derivative of f (x) respect to x. it to taking derivatives, we use Leibniz notation. is, d y d x derivative of function y (x), respect to x. we y (or y (x)) we x by a little bit
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Let, y = eu and u = − x. ∴ dy du = eu and du dx = − 1. Using Rule: dy dx = dy du ⋅ du dx. ∴ dy dx = eu ×(−1) = −eu. Subst, back u = − x. ∴ dy dx = −e−x.
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